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		<title>Fermat&#8217;s Little Theorem implies Wilson&#8217;s Theorem</title>
		<link>http://disquisitionesmathematicae.wordpress.com/2009/05/02/fermats-little-theorem-implies-wilsons-theorem/</link>
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		<pubDate>Sat, 02 May 2009 08:44:06 +0000</pubDate>
		<dc:creator>disquisitionesmathematicae</dc:creator>
				<category><![CDATA[Number Theory]]></category>
		<category><![CDATA[congruences]]></category>
		<category><![CDATA[Fermat]]></category>
		<category><![CDATA[Little theorem]]></category>
		<category><![CDATA[Pascal's identity]]></category>
		<category><![CDATA[Wilson's theorem]]></category>

		<guid isPermaLink="false">http://disquisitionesmathematicae.wordpress.com/?p=69</guid>
		<description><![CDATA[I came across this novel argument in a book last year. It basically exploits the identity, Wilson&#8217;s theorem states that The result is true for . So we may assume . We then conveniently consider the above expression for . Choosing we get Using Fermat&#8217;s little theorem and the fact that &#8216;p&#8217; is odd we [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=disquisitionesmathematicae.wordpress.com&amp;blog=7536994&amp;post=69&amp;subd=disquisitionesmathematicae&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>I came across this novel argument in a book last year. It basically exploits the identity,</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Csum_%7Bi%3D0%7D%5E%7Bn%7D+%28-1%29%5E%7Bi%7D%7B%7Bn%7D%5Cchoose%7Bi%7D%7D+%28x-i%29%5E%7Bn%7D%3Dn%21%5C+%5Cforall%7B%5C+n%5Cgeq%7B0%7D%2Cx%5Cin%7B%5Cmathbb%7BR%7D%7D%7D&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;sum_{i=0}^{n} (-1)^{i}{{n}&#92;choose{i}} (x-i)^{n}=n!&#92; &#92;forall{&#92; n&#92;geq{0},x&#92;in{&#92;mathbb{R}}}' title='&#92;displaystyle &#92;sum_{i=0}^{n} (-1)^{i}{{n}&#92;choose{i}} (x-i)^{n}=n!&#92; &#92;forall{&#92; n&#92;geq{0},x&#92;in{&#92;mathbb{R}}}' class='latex' /></p>
<p>Wilson&#8217;s theorem states that</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%28p-1%29%21%5Cequiv+-1+%5C+%28mod+%5C+p%29&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle (p-1)!&#92;equiv -1 &#92; (mod &#92; p)' title='&#92;displaystyle (p-1)!&#92;equiv -1 &#92; (mod &#92; p)' class='latex' /></p>
<p>The result is true for <img src='http://s0.wp.com/latex.php?latex=p%3D2&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='p=2' title='p=2' class='latex' />. So we may assume <img src='http://s0.wp.com/latex.php?latex=p%3E2&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='p&gt;2' title='p&gt;2' class='latex' />. We then conveniently consider the above expression for <img src='http://s0.wp.com/latex.php?latex=n%3Dp-1&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='n=p-1' title='n=p-1' class='latex' />.</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle%5Csum_%7Bi%3D0%7D%5E%7Bp-1%7D+%28-1%29%5E%7Bi%7D%7B%7Bp-1%7D%5Cchoose%7Bi%7D%7D+%28x-i%29%5E%7Bp-1%7D%3D%28p-1%29%21&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle&#92;sum_{i=0}^{p-1} (-1)^{i}{{p-1}&#92;choose{i}} (x-i)^{p-1}=(p-1)!' title='&#92;displaystyle&#92;sum_{i=0}^{p-1} (-1)^{i}{{p-1}&#92;choose{i}} (x-i)^{p-1}=(p-1)!' class='latex' /></p>
<p>Choosing <img src='http://s0.wp.com/latex.php?latex=x%3D0&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='x=0' title='x=0' class='latex' /> we get</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle%5Csum_%7Bi%3D0%7D%5E%7Bp-1%7D+%28-1%29%5E%7Bi%7D%7B%7Bp-1%7D%5Cchoose%7Bi%7D%7D+%28-i%29%5E%7Bp-1%7D%3D%28p-1%29%21&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle&#92;sum_{i=0}^{p-1} (-1)^{i}{{p-1}&#92;choose{i}} (-i)^{p-1}=(p-1)!' title='&#92;displaystyle&#92;sum_{i=0}^{p-1} (-1)^{i}{{p-1}&#92;choose{i}} (-i)^{p-1}=(p-1)!' class='latex' /></p>
<p>Using Fermat&#8217;s little theorem and the fact that &#8216;p&#8217; is odd we get,</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle%5Csum_%7Bi%3D1%7D%5E%7Bp-1%7D+%28-1%29%5E%7Bi%7D%7B%7Bp-1%7D%5Cchoose%7Bi%7D%7D+%5Cequiv+%28p-1%29%21+%5C+%28mod+%5C+p%29&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle&#92;sum_{i=1}^{p-1} (-1)^{i}{{p-1}&#92;choose{i}} &#92;equiv (p-1)! &#92; (mod &#92; p)' title='&#92;displaystyle&#92;sum_{i=1}^{p-1} (-1)^{i}{{p-1}&#92;choose{i}} &#92;equiv (p-1)! &#92; (mod &#92; p)' class='latex' /></p>
<p>The Pascal&#8217;s identity,</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle%7B%7Bp%7D%5Cchoose%7Bi%7D%7D%3D%7B%7Bp-1%7D%5Cchoose%7Bi%7D%7D%2B%7B%7Bp-1%7D%5Cchoose%7Bi-1%7D%7D&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle{{p}&#92;choose{i}}={{p-1}&#92;choose{i}}+{{p-1}&#92;choose{i-1}}' title='&#92;displaystyle{{p}&#92;choose{i}}={{p-1}&#92;choose{i}}+{{p-1}&#92;choose{i-1}}' class='latex' /></p>
<p>then implies,</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle%7B%7Bp-1%7D%5Cchoose%7Bi%7D%7D%5Cequiv-%7B%7Bp-1%7D%5Cchoose%7Bi-1%7D%7D%28mod%5C+p%29&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle{{p-1}&#92;choose{i}}&#92;equiv-{{p-1}&#92;choose{i-1}}(mod&#92; p)' title='&#92;displaystyle{{p-1}&#92;choose{i}}&#92;equiv-{{p-1}&#92;choose{i-1}}(mod&#92; p)' class='latex' /></p>
<p>And since <img src='http://s0.wp.com/latex.php?latex=%7B%7Bp-1%7D%5Cchoose%7B0%7D%7D%5Cequiv+1&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='{{p-1}&#92;choose{0}}&#92;equiv 1' title='{{p-1}&#92;choose{0}}&#92;equiv 1' class='latex' /> it follows that</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle%7B%7Bp-1%7D%5Cchoose%7Bi%7D%7D%5Cequiv%7B%28-1%29%5E%7Bi%7D%7D&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle{{p-1}&#92;choose{i}}&#92;equiv{(-1)^{i}}' title='&#92;displaystyle{{p-1}&#92;choose{i}}&#92;equiv{(-1)^{i}}' class='latex' /></p>
<p>Therefore,</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle%5Csum_%7Bi%3D1%7D%5E%7Bp-1%7D+%28-1%29%5E%7Bi%7D%7B%7Bp-1%7D%5Cchoose%7Bi%7D%7D%5Cequiv%5Csum_%7Bi%3D1%7D%5E%7Bp-1%7D+%28-1%29%5E%7Bi%7D%28-1%29%5E%7Bi%7D%3D%5Csum_%7Bi%3D1%7D%5E%7Bp-1%7D1%5Cequiv+%28p-1%29%21&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle&#92;sum_{i=1}^{p-1} (-1)^{i}{{p-1}&#92;choose{i}}&#92;equiv&#92;sum_{i=1}^{p-1} (-1)^{i}(-1)^{i}=&#92;sum_{i=1}^{p-1}1&#92;equiv (p-1)!' title='&#92;displaystyle&#92;sum_{i=1}^{p-1} (-1)^{i}{{p-1}&#92;choose{i}}&#92;equiv&#92;sum_{i=1}^{p-1} (-1)^{i}(-1)^{i}=&#92;sum_{i=1}^{p-1}1&#92;equiv (p-1)!' class='latex' /></p>
<p>And thus,</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle%28p-1%29%21%5Cequiv+%28p-1%29%5Cequiv+-1+%28mod%5C+p%29&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle(p-1)!&#92;equiv (p-1)&#92;equiv -1 (mod&#92; p)' title='&#92;displaystyle(p-1)!&#92;equiv (p-1)&#92;equiv -1 (mod&#92; p)' class='latex' /></p>
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		<title>Counting and the Lagrange identity.</title>
		<link>http://disquisitionesmathematicae.wordpress.com/2009/04/29/counting-and-the-lagrange-identity/</link>
		<comments>http://disquisitionesmathematicae.wordpress.com/2009/04/29/counting-and-the-lagrange-identity/#comments</comments>
		<pubDate>Wed, 29 Apr 2009 18:04:32 +0000</pubDate>
		<dc:creator>disquisitionesmathematicae</dc:creator>
				<category><![CDATA[Analysis]]></category>
		<category><![CDATA[Cauchy]]></category>
		<category><![CDATA[Cauchy-Schwarz Inequality]]></category>
		<category><![CDATA[counting]]></category>

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		<description><![CDATA[This is a prime example of how a proof for a general argument can be worked out by considering simple cases. The Lagrange identity for says that We will analyze the case for n=3. It will provide a beautiful outline for a general proof. The left hand side of the equality (1) will be equal [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=disquisitionesmathematicae.wordpress.com&amp;blog=7536994&amp;post=30&amp;subd=disquisitionesmathematicae&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>This is a prime example of how a proof for a general argument can be worked out by considering simple cases. The Lagrange identity for <img src='http://s0.wp.com/latex.php?latex=%5Cmathbb%7BC%7D&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;mathbb{C}' title='&#92;mathbb{C}' class='latex' /> says that</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%7C%5Csum_%7Bi%3D0%7D%5E%7Bn%7D+a_%7Bi%7Db_%7Bi%7D%7C%5E%7B2%7D%3D%5Csum_%7Bi%3D0%7D%5E%7Bn%7D+%7Ca_%7Bi%7D%7C%5E%7B2%7D%5Csum_%7Bi%3D0%7D%5E%7Bn%7D+%7Cb_%7Bi%7D%7C%5E%7B2%7D-%5Csum_%7B1+%5Cleq%7Bi%7D%3Cj%5Cleq%7Bn%7D%7D+%7Ca_%7Bi%7D%5Coverline%7Bb_%7Bj%7D%7D-a_%7Bj%7D%5Coverline%7Bb_%7Bi%7D%7D%7C%5E%7B2%7D%5C+%5C+%5C+%5C+%5C+%281%29&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle |&#92;sum_{i=0}^{n} a_{i}b_{i}|^{2}=&#92;sum_{i=0}^{n} |a_{i}|^{2}&#92;sum_{i=0}^{n} |b_{i}|^{2}-&#92;sum_{1 &#92;leq{i}&lt;j&#92;leq{n}} |a_{i}&#92;overline{b_{j}}-a_{j}&#92;overline{b_{i}}|^{2}&#92; &#92; &#92; &#92; &#92; (1)' title='&#92;displaystyle |&#92;sum_{i=0}^{n} a_{i}b_{i}|^{2}=&#92;sum_{i=0}^{n} |a_{i}|^{2}&#92;sum_{i=0}^{n} |b_{i}|^{2}-&#92;sum_{1 &#92;leq{i}&lt;j&#92;leq{n}} |a_{i}&#92;overline{b_{j}}-a_{j}&#92;overline{b_{i}}|^{2}&#92; &#92; &#92; &#92; &#92; (1)' class='latex' /></p>
<p>We will analyze the case for n=3. It will provide a beautiful outline for a general proof.</p>
<p>The left hand side of the equality (1) will be equal to</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%7Ca_%7B1%7Db_%7B1%7D+%2Ba_%7B2%7Db_%7B2%7D%2Ba_%7B3%7Db_%7B3%7D%7C%5E%7B2%7D%3D%28a_%7B1%7Db_%7B1%7D+%2Ba_%7B2%7Db_%7B2%7D%2Ba_%7B3%7Db_%7B3%7D%29%28%5Coverline%7Ba_%7B1%7Db_%7B1%7D%7D%2B%5Coverline%7Ba_%7B2%7Db_%7B2%7D%7D%2B%5Coverline%7Ba_%7B3%7Db_%7B3%7D%7D%29%5C+%5C++%282%29&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle |a_{1}b_{1} +a_{2}b_{2}+a_{3}b_{3}|^{2}=(a_{1}b_{1} +a_{2}b_{2}+a_{3}b_{3})(&#92;overline{a_{1}b_{1}}+&#92;overline{a_{2}b_{2}}+&#92;overline{a_{3}b_{3}})&#92; &#92;  (2)' title='&#92;displaystyle |a_{1}b_{1} +a_{2}b_{2}+a_{3}b_{3}|^{2}=(a_{1}b_{1} +a_{2}b_{2}+a_{3}b_{3})(&#92;overline{a_{1}b_{1}}+&#92;overline{a_{2}b_{2}}+&#92;overline{a_{3}b_{3}})&#92; &#92;  (2)' class='latex' /></p>
<p>It would be helpful indeed to consider the following 3 x 3 matrix for the sum of all the elements of this matrix is equal to the LHS of (2).</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cleft%28%5Cbegin%7Barray%7D%7Bccc%7Da_%7B1%7D%5Coverline%7Ba_%7B1%7D%7Db_%7B1%7D++%5Coverline%7Bb_%7B1%7D%7D%26a_%7B1%7D%5Coverline%7Ba_%7B2%7D%7Db_%7B1%7D%5Coverline%7Bb_%7B2%7D%7D%26a_%7B1%7D%5Coverline%7Ba_%7B3%7D%7Db_%7B1%7D%5Coverline%7Bb_%7B3%7D%7D%5C%5C+a_%7B2%7D%5Coverline%7Ba_%7B1%7D%7Db_%7B2%7D%5Coverline%7Bb_%7B1%7D%7D%26a_%7B2%7D%5Coverline%7Ba_%7B2%7D%7Db_%7B2%7D%5Coverline%7Bb_%7B2%7D%7D%26a_%7B2%7D%5Coverline%7Ba_%7B3%7D%7Db_%7B2%7D%5Coverline%7Bb_%7B3%7D%7D%5C%5C+a_%7B3%7D%5Coverline%7Ba_%7B1%7D%7Db_%7B3%7D%5Coverline%7Bb_%7B1%7D%7D%26a_%7B3%7D%5Coverline%7Ba_%7B2%7D%7Db_%7B3%7D%5Coverline%7Bb_%7B2%7D%7D%26a_%7B3%7D%5Coverline%7Ba_%7B3%7D%7Db_%7B3%7D%5Coverline%7Bb_%7B3%7D%7D%5Cend%7Barray%7D%5Cright%29&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;left(&#92;begin{array}{ccc}a_{1}&#92;overline{a_{1}}b_{1}  &#92;overline{b_{1}}&amp;a_{1}&#92;overline{a_{2}}b_{1}&#92;overline{b_{2}}&amp;a_{1}&#92;overline{a_{3}}b_{1}&#92;overline{b_{3}}&#92;&#92; a_{2}&#92;overline{a_{1}}b_{2}&#92;overline{b_{1}}&amp;a_{2}&#92;overline{a_{2}}b_{2}&#92;overline{b_{2}}&amp;a_{2}&#92;overline{a_{3}}b_{2}&#92;overline{b_{3}}&#92;&#92; a_{3}&#92;overline{a_{1}}b_{3}&#92;overline{b_{1}}&amp;a_{3}&#92;overline{a_{2}}b_{3}&#92;overline{b_{2}}&amp;a_{3}&#92;overline{a_{3}}b_{3}&#92;overline{b_{3}}&#92;end{array}&#92;right)' title='&#92;displaystyle &#92;left(&#92;begin{array}{ccc}a_{1}&#92;overline{a_{1}}b_{1}  &#92;overline{b_{1}}&amp;a_{1}&#92;overline{a_{2}}b_{1}&#92;overline{b_{2}}&amp;a_{1}&#92;overline{a_{3}}b_{1}&#92;overline{b_{3}}&#92;&#92; a_{2}&#92;overline{a_{1}}b_{2}&#92;overline{b_{1}}&amp;a_{2}&#92;overline{a_{2}}b_{2}&#92;overline{b_{2}}&amp;a_{2}&#92;overline{a_{3}}b_{2}&#92;overline{b_{3}}&#92;&#92; a_{3}&#92;overline{a_{1}}b_{3}&#92;overline{b_{1}}&amp;a_{3}&#92;overline{a_{2}}b_{3}&#92;overline{b_{2}}&amp;a_{3}&#92;overline{a_{3}}b_{3}&#92;overline{b_{3}}&#92;end{array}&#92;right)' class='latex' />
<p align="center"></p>
<p>In fact, the elements of the matrix are the terms on the RHS in (2).</p>
<p>Each term of the matrix above can thus be represented as</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+A_%7Bij%7D%3Da_%7Bi%7D%5Coverline%7Ba_%7Bj%7D%7Db_%7Bi%7D%5Coverline%7Bb_%7Bj%7D%7D&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle A_{ij}=a_{i}&#92;overline{a_{j}}b_{i}&#92;overline{b_{j}}' title='&#92;displaystyle A_{ij}=a_{i}&#92;overline{a_{j}}b_{i}&#92;overline{b_{j}}' class='latex' /></p>
<p>Now consider the first term on the RHS in (1). For n=3, it is</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%28%7Ca_%7B1%7D%7C%5E%7B2%7D%2B%7Ca_%7B2%7D%7C%5E%7B2%7D%2B%7Ca_%7B3%7D%7C%5E%7B2%7D%29%28%7Cb_%7B1%7D%7C%5E%7B2%7D%2B%7Cb_%7B2%7D%7C%5E%7B2%7D%2B%7Cb_%7B3%7D%7C%5E%7B2%7D%29&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle (|a_{1}|^{2}+|a_{2}|^{2}+|a_{3}|^{2})(|b_{1}|^{2}+|b_{2}|^{2}+|b_{3}|^{2})' title='&#92;displaystyle (|a_{1}|^{2}+|a_{2}|^{2}+|a_{3}|^{2})(|b_{1}|^{2}+|b_{2}|^{2}+|b_{3}|^{2})' class='latex' /></p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle%3D%28a_%7B1%7D%5Coverline%7Ba_%7B1%7D%7D%2Ba_%7B2%7D%5Coverline%7Ba_%7B2%7D%7D%2Ba_%7B3%7D%5Coverline%7Ba_%7B3%7D%7D%29%28b_%7B1%7D%5Coverline%7Bb_%7B1%7D%7D%2Bb_%7B2%7D%5Coverline%7Bb_%7B2%7D%7D%2Bb_%7B3%7D%5Coverline%7Bb_%7B3%7D%7D%29%5C+%5C+%5C+%283%29&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle=(a_{1}&#92;overline{a_{1}}+a_{2}&#92;overline{a_{2}}+a_{3}&#92;overline{a_{3}})(b_{1}&#92;overline{b_{1}}+b_{2}&#92;overline{b_{2}}+b_{3}&#92;overline{b_{3}})&#92; &#92; &#92; (3)' title='&#92;displaystyle=(a_{1}&#92;overline{a_{1}}+a_{2}&#92;overline{a_{2}}+a_{3}&#92;overline{a_{3}})(b_{1}&#92;overline{b_{1}}+b_{2}&#92;overline{b_{2}}+b_{3}&#92;overline{b_{3}})&#92; &#92; &#92; (3)' class='latex' /></p>
<p>Again, as above, it would be helpful to consider the following matrix.</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cleft%28%5Cbegin%7Barray%7D%7Bccc%7Da_%7B1%7D%5Coverline%7Ba_%7B1%7D%7Db_%7B1%7D%5Coverline%7Bb_%7B1%7D%7D%26a_%7B1%7D%5Coverline%7Ba_%7B1%7D%7Db_%7B2%7D%5Coverline%7Bb_%7B2%7D%7D%26a_%7B1%7D%5Coverline%7Ba_%7B1%7D%7Db_%7B3%7D%5Coverline%7Bb_%7B3%7D%7D%5C%5C+a_%7B2%7D%5Coverline%7Ba_%7B2%7D%7Db_%7B1%7D%5Coverline%7Bb_%7B1%7D%7D%26a_%7B2%7D%5Coverline%7Ba_%7B2%7D%7Db_%7B2%7D%5Coverline%7Bb_%7B2%7D%7D%26a_%7B2%7D%5Coverline%7Ba_%7B2%7D%7Db_%7B3%7D%5Coverline%7Bb_%7B3%7D%7D%5C%5C+a_%7B3%7D%5Coverline%7Ba_%7B3%7D%7Db_%7B1%7D%5Coverline%7Bb_%7B1%7D%7D%26a_%7B3%7D%5Coverline%7Ba_%7B3%7D%7Db_%7B2%7D%5Coverline%7Bb_%7B2%7D%7D%26a_%7B3%7D%5Coverline%7Ba_%7B3%7D%7Db_%7B3%7D%5Coverline%7Bb_%7B3%7D%7D%5Cend%7Barray%7D%5Cright%29&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;left(&#92;begin{array}{ccc}a_{1}&#92;overline{a_{1}}b_{1}&#92;overline{b_{1}}&amp;a_{1}&#92;overline{a_{1}}b_{2}&#92;overline{b_{2}}&amp;a_{1}&#92;overline{a_{1}}b_{3}&#92;overline{b_{3}}&#92;&#92; a_{2}&#92;overline{a_{2}}b_{1}&#92;overline{b_{1}}&amp;a_{2}&#92;overline{a_{2}}b_{2}&#92;overline{b_{2}}&amp;a_{2}&#92;overline{a_{2}}b_{3}&#92;overline{b_{3}}&#92;&#92; a_{3}&#92;overline{a_{3}}b_{1}&#92;overline{b_{1}}&amp;a_{3}&#92;overline{a_{3}}b_{2}&#92;overline{b_{2}}&amp;a_{3}&#92;overline{a_{3}}b_{3}&#92;overline{b_{3}}&#92;end{array}&#92;right)' title='&#92;displaystyle &#92;left(&#92;begin{array}{ccc}a_{1}&#92;overline{a_{1}}b_{1}&#92;overline{b_{1}}&amp;a_{1}&#92;overline{a_{1}}b_{2}&#92;overline{b_{2}}&amp;a_{1}&#92;overline{a_{1}}b_{3}&#92;overline{b_{3}}&#92;&#92; a_{2}&#92;overline{a_{2}}b_{1}&#92;overline{b_{1}}&amp;a_{2}&#92;overline{a_{2}}b_{2}&#92;overline{b_{2}}&amp;a_{2}&#92;overline{a_{2}}b_{3}&#92;overline{b_{3}}&#92;&#92; a_{3}&#92;overline{a_{3}}b_{1}&#92;overline{b_{1}}&amp;a_{3}&#92;overline{a_{3}}b_{2}&#92;overline{b_{2}}&amp;a_{3}&#92;overline{a_{3}}b_{3}&#92;overline{b_{3}}&#92;end{array}&#92;right)' class='latex' /></p>
<p>The elements of this matrix are again the terms on RHS in (3).</p>
<p>We can thus call each of them</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+B_%7Bij%7D%3Da_%7Bi%7D%5Coverline%7Ba_%7Bi%7D%7Db_%7Bj%7D%5Coverline%7Bb_%7Bj%7D%7D&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle B_{ij}=a_{i}&#92;overline{a_{i}}b_{j}&#92;overline{b_{j}}' title='&#92;displaystyle B_{ij}=a_{i}&#92;overline{a_{i}}b_{j}&#92;overline{b_{j}}' class='latex' /></p>
<p>The last term in (1) is</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+-%28%7Ca_%7B1%7D%5Coverline%7Bb_%7B2%7D%7D-a_%7B2%7D%5Coverline%7Bb_%7B1%7D%7D%7C%5E%7B2%7D%2B%7Ca_%7B1%7D%5Coverline%7Bb_%7B3%7D%7D-a_%7B3%7D%5Coverline%7Bb_%7B1%7D%7D%7C%5E%7B2%7D%2B%7Ca_%7B2%7D%5Coverline%7Bb_%7B3%7D%7D-a_%7B3%7D%5Coverline%7Bb_%7B2%7D%7D%7C%5E%7B2%7D%29%5C+%5C+%5C+%284%29&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle -(|a_{1}&#92;overline{b_{2}}-a_{2}&#92;overline{b_{1}}|^{2}+|a_{1}&#92;overline{b_{3}}-a_{3}&#92;overline{b_{1}}|^{2}+|a_{2}&#92;overline{b_{3}}-a_{3}&#92;overline{b_{2}}|^{2})&#92; &#92; &#92; (4)' title='&#92;displaystyle -(|a_{1}&#92;overline{b_{2}}-a_{2}&#92;overline{b_{1}}|^{2}+|a_{1}&#92;overline{b_{3}}-a_{3}&#92;overline{b_{1}}|^{2}+|a_{2}&#92;overline{b_{3}}-a_{3}&#92;overline{b_{2}}|^{2})&#92; &#92; &#92; (4)' class='latex' /></p>
<p>This time we use two matrices to organize the terms in (4).</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cleft%28%5Cbegin%7Barray%7D%7Bccc%7D0%26a_%7B1%7D%5Coverline%7Ba_%7B2%7D%7Db_%7B1%7D%5Coverline%7Bb_%7B2%7D%7D%26a_%7B1%7D%5Coverline%7Ba_%7B3%7D%7Db_%7B1%7D%5Coverline%7Bb_%7B3%7D%7D%5C%5C+a_%7B2%7D%5Coverline%7Ba_%7B1%7D%7Db_%7B2%7D%5Coverline%7Bb_%7B1%7D%7D%260%26a_%7B2%7D%5Coverline%7Ba_%7B3%7D%7Db_%7B2%7D%5Coverline%7Bb_%7B3%7D%7D%5C%5C+a_%7B3%7D%5Coverline%7Ba_%7B1%7D%7Db_%7B3%7D%5Coverline%7Bb_%7B1%7D%7D%26a_%7B3%7D%5Coverline%7Ba_%7B2%7D%7Db_%7B3%7D%5Coverline%7Bb_%7B2%7D%7D%260%5Cend%7Barray%7D%5Cright%29&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;left(&#92;begin{array}{ccc}0&amp;a_{1}&#92;overline{a_{2}}b_{1}&#92;overline{b_{2}}&amp;a_{1}&#92;overline{a_{3}}b_{1}&#92;overline{b_{3}}&#92;&#92; a_{2}&#92;overline{a_{1}}b_{2}&#92;overline{b_{1}}&amp;0&amp;a_{2}&#92;overline{a_{3}}b_{2}&#92;overline{b_{3}}&#92;&#92; a_{3}&#92;overline{a_{1}}b_{3}&#92;overline{b_{1}}&amp;a_{3}&#92;overline{a_{2}}b_{3}&#92;overline{b_{2}}&amp;0&#92;end{array}&#92;right)' title='&#92;displaystyle &#92;left(&#92;begin{array}{ccc}0&amp;a_{1}&#92;overline{a_{2}}b_{1}&#92;overline{b_{2}}&amp;a_{1}&#92;overline{a_{3}}b_{1}&#92;overline{b_{3}}&#92;&#92; a_{2}&#92;overline{a_{1}}b_{2}&#92;overline{b_{1}}&amp;0&amp;a_{2}&#92;overline{a_{3}}b_{2}&#92;overline{b_{3}}&#92;&#92; a_{3}&#92;overline{a_{1}}b_{3}&#92;overline{b_{1}}&amp;a_{3}&#92;overline{a_{2}}b_{3}&#92;overline{b_{2}}&amp;0&#92;end{array}&#92;right)' class='latex' /></p>
<p>and</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Cleft%28%5Cbegin%7Barray%7D%7Bccc%7D0%26a_%7B1%7D%5Coverline%7Ba_%7B1%7D%7Db_%7B2%7D%5Coverline%7Bb_%7B2%7D%7D%26a_%7B1%7D%5Coverline%7Ba_%7B1%7D%7Db_%7B3%7D%5Coverline%7Bb_%7B3%7D%7D%5C%5C+a_%7B2%7D%5Coverline%7Ba_%7B2%7D%7Db_%7B1%7D%5Coverline%7Bb_%7B1%7D%7D%260%26a_%7B2%7D%5Coverline%7Ba_%7B2%7D%7Db_%7B3%7D%5Coverline%7Bb_%7B3%7D%7D%5C%5C+a_%7B3%7D%5Coverline%7Ba_%7B3%7D%7Db_%7B1%7D%5Coverline%7Bb_%7B1%7D%7D%26a_%7B3%7D%5Coverline%7Ba_%7B3%7D%7Db_%7B2%7D%5Coverline%7Bb_%7B2%7D%7D%260%5Cend%7Barray%7D%5Cright%29&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;left(&#92;begin{array}{ccc}0&amp;a_{1}&#92;overline{a_{1}}b_{2}&#92;overline{b_{2}}&amp;a_{1}&#92;overline{a_{1}}b_{3}&#92;overline{b_{3}}&#92;&#92; a_{2}&#92;overline{a_{2}}b_{1}&#92;overline{b_{1}}&amp;0&amp;a_{2}&#92;overline{a_{2}}b_{3}&#92;overline{b_{3}}&#92;&#92; a_{3}&#92;overline{a_{3}}b_{1}&#92;overline{b_{1}}&amp;a_{3}&#92;overline{a_{3}}b_{2}&#92;overline{b_{2}}&amp;0&#92;end{array}&#92;right)' title='&#92;displaystyle &#92;left(&#92;begin{array}{ccc}0&amp;a_{1}&#92;overline{a_{1}}b_{2}&#92;overline{b_{2}}&amp;a_{1}&#92;overline{a_{1}}b_{3}&#92;overline{b_{3}}&#92;&#92; a_{2}&#92;overline{a_{2}}b_{1}&#92;overline{b_{1}}&amp;0&amp;a_{2}&#92;overline{a_{2}}b_{3}&#92;overline{b_{3}}&#92;&#92; a_{3}&#92;overline{a_{3}}b_{1}&#92;overline{b_{1}}&amp;a_{3}&#92;overline{a_{3}}b_{2}&#92;overline{b_{2}}&amp;0&#92;end{array}&#92;right)' class='latex' /></p>
<p>And we thus define elements of the first and the second matrix respectively as</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+C_%7Bij%7D%3Da_%7Bi%7D%5Coverline%7Ba_%7Bj%7D%7Db_%7Bi%7D%5Coverline%7Bb_%7Bj%7D%7D%5Csigma_%7Bij%7D&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle C_{ij}=a_{i}&#92;overline{a_{j}}b_{i}&#92;overline{b_{j}}&#92;sigma_{ij}' title='&#92;displaystyle C_{ij}=a_{i}&#92;overline{a_{j}}b_{i}&#92;overline{b_{j}}&#92;sigma_{ij}' class='latex' /></p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+D_%7Bij%7D%3Da_%7Bi%7D%5Coverline%7Ba_%7Bi%7D%7Db_%7Bj%7D%5Coverline%7Bb_%7Bj%7D%7D%5Csigma_%7Bij%7D&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle D_{ij}=a_{i}&#92;overline{a_{i}}b_{j}&#92;overline{b_{j}}&#92;sigma_{ij}' title='&#92;displaystyle D_{ij}=a_{i}&#92;overline{a_{i}}b_{j}&#92;overline{b_{j}}&#92;sigma_{ij}' class='latex' /></p>
<p>where we define <img src='http://s0.wp.com/latex.php?latex=%5Csigma_%7Bij%7D&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;sigma_{ij}' title='&#92;sigma_{ij}' class='latex' /> as</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Csigma_%7Bij%7D%3D0%5C+%5Cmathrm%7Bif%7D%5C+i%3Dj&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;sigma_{ij}=0&#92; &#92;mathrm{if}&#92; i=j' title='&#92;displaystyle &#92;sigma_{ij}=0&#92; &#92;mathrm{if}&#92; i=j' class='latex' /></p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Csigma_%7Bij%7D%3D1%5C+%5Cmathrm%7Bif%7D%5C+i%5Cnot%3Dj&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;sigma_{ij}=1&#92; &#92;mathrm{if}&#92; i&#92;not=j' title='&#92;displaystyle &#92;sigma_{ij}=1&#92; &#92;mathrm{if}&#92; i&#92;not=j' class='latex' /></p>
<p>Now let</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+T_%7Bij%7D%3DA_%7Bij%7D%2BD_%7Bij%7D-B_%7Bij%7D-C_%7Bij%7D&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle T_{ij}=A_{ij}+D_{ij}-B_{ij}-C_{ij}' title='&#92;displaystyle T_{ij}=A_{ij}+D_{ij}-B_{ij}-C_{ij}' class='latex' /></p>
<p>Therefore,</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+T_%7Bij%7D%3DA_%7Bij%7D%28%5Cdelta_%7Bij%7D%2B%5Csigma_%7Bij%7D%29%2BD_%7Bij%7D-B_%7Bij%7D%28%5Cdelta_%7Bij%7D%2B%5Csigma_%7Bij%7D%29-C_%7Bij%7D&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle T_{ij}=A_{ij}(&#92;delta_{ij}+&#92;sigma_{ij})+D_{ij}-B_{ij}(&#92;delta_{ij}+&#92;sigma_{ij})-C_{ij}' title='&#92;displaystyle T_{ij}=A_{ij}(&#92;delta_{ij}+&#92;sigma_{ij})+D_{ij}-B_{ij}(&#92;delta_{ij}+&#92;sigma_{ij})-C_{ij}' class='latex' /></p>
<p>where we have used <img src='http://s0.wp.com/latex.php?latex=%5Cdelta_%7Bij%7D%2B%5Csigma_%7Bij%7D%3D1&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;delta_{ij}+&#92;sigma_{ij}=1' title='&#92;delta_{ij}+&#92;sigma_{ij}=1' class='latex' /> (<img src='http://s0.wp.com/latex.php?latex=%5Cdelta_%7Bij%7D&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;delta_{ij}' title='&#92;delta_{ij}' class='latex' /> is the Kronecker delta)</p>
<p>And so,</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+T_%7Bij%7D%3Da_%7Bi%7D%5Coverline%7Ba_%7Bj%7D%7Db_%7Bi%7D%5Coverline%7Bb_%7Bj%7D%7D%5Cdelta_%7Bij%7D%2Ba_%7Bi%7D%5Coverline%7Ba_%7Bj%7D%7Db_%7Bi%7D%5Coverline%7Bb_%7Bj%7D%7D%5Csigma_%7Bij%7D%2Ba_%7Bi%7D%5Coverline%7Ba_%7Bi%7D%7Db_%7Bj%7D%5Coverline%7Bb_%7Bj%7D%7D%5Csigma_%7Bij%7D&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle T_{ij}=a_{i}&#92;overline{a_{j}}b_{i}&#92;overline{b_{j}}&#92;delta_{ij}+a_{i}&#92;overline{a_{j}}b_{i}&#92;overline{b_{j}}&#92;sigma_{ij}+a_{i}&#92;overline{a_{i}}b_{j}&#92;overline{b_{j}}&#92;sigma_{ij}' title='&#92;displaystyle T_{ij}=a_{i}&#92;overline{a_{j}}b_{i}&#92;overline{b_{j}}&#92;delta_{ij}+a_{i}&#92;overline{a_{j}}b_{i}&#92;overline{b_{j}}&#92;sigma_{ij}+a_{i}&#92;overline{a_{i}}b_{j}&#92;overline{b_{j}}&#92;sigma_{ij}' class='latex' /></p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+-a_%7Bi%7D%5Coverline%7Ba_%7Bi%7D%7Db_%7Bj%7D%5Coverline%7Bb_%7Bj%7D%7D%5Cdelta_%7Bij%7D-a_%7Bi%7D%5Coverline%7Ba_%7Bi%7D%7Db_%7Bj%7D%5Coverline%7Bb_%7Bj%7D%7D%5Csigma_%7Bij%7D-a_%7Bi%7D%5Coverline%7Ba_%7Bj%7D%7Db_%7Bi%7D%5Coverline%7Bb_%7Bj%7D%7D%5Csigma_%7Bij%7D&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle -a_{i}&#92;overline{a_{i}}b_{j}&#92;overline{b_{j}}&#92;delta_{ij}-a_{i}&#92;overline{a_{i}}b_{j}&#92;overline{b_{j}}&#92;sigma_{ij}-a_{i}&#92;overline{a_{j}}b_{i}&#92;overline{b_{j}}&#92;sigma_{ij}' title='&#92;displaystyle -a_{i}&#92;overline{a_{i}}b_{j}&#92;overline{b_{j}}&#92;delta_{ij}-a_{i}&#92;overline{a_{i}}b_{j}&#92;overline{b_{j}}&#92;sigma_{ij}-a_{i}&#92;overline{a_{j}}b_{i}&#92;overline{b_{j}}&#92;sigma_{ij}' class='latex' /></p>
<p>or</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+T_%7Bij%7D%3Da_%7Bi%7D%5Coverline%7Ba_%7Bi%7D%7Db_%7Bi%7D%5Coverline%7Bb_%7Bi%7D%7D-a_%7Bi%7D%5Coverline%7Ba_%7Bi%7D%7Db_%7Bi%7D%5Coverline%7Bb_%7Bi%7D%7D%3D0&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle T_{ij}=a_{i}&#92;overline{a_{i}}b_{i}&#92;overline{b_{i}}-a_{i}&#92;overline{a_{i}}b_{i}&#92;overline{b_{i}}=0' title='&#92;displaystyle T_{ij}=a_{i}&#92;overline{a_{i}}b_{i}&#92;overline{b_{i}}-a_{i}&#92;overline{a_{i}}b_{i}&#92;overline{b_{i}}=0' class='latex' /></p>
<p>Since each <img src='http://s0.wp.com/latex.php?latex=T_%7Bij%7D&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='T_{ij}' title='T_{ij}' class='latex' /> is zero the sum</p>
<p align="center"><img src='http://s0.wp.com/latex.php?latex=%5Cdisplaystyle+%5Csum_%7Bi%2Cj%3D1%7D%5E%7Bn%7DT_%7Bij%7D%3D0&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;displaystyle &#92;sum_{i,j=1}^{n}T_{ij}=0' title='&#92;displaystyle &#92;sum_{i,j=1}^{n}T_{ij}=0' class='latex' /></p>
<p>which automatically implies the Lagrange Identity in <img src='http://s0.wp.com/latex.php?latex=%5Cmathbb%7BC%7D&amp;bg=f2e1c3&amp;fg=000000&amp;s=0' alt='&#92;mathbb{C}' title='&#92;mathbb{C}' class='latex' />.</p>
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